Ref: https://stackoverflow.com/questions/35610053/jenkins-delete-builds-older-than-latest-20-builds-for-all-jobs
You can use the Jenkins Script Console to iterate through all jobs, get a list of the N most recent and perform some action on the others.
import jenkins.model.Jenkins
import hudson.model.Job
MAX_BUILDS = 20
for (job in Jenkins.instance.items) {
println job.name
def recent = job.builds.limit(MAX_BUILDS)
for (build in job.builds) {
if (!recent.contains(build)) {
println "Preparing to delete: " + build
// build.delete()
}
}
}
The Jenkins Script Console is a great tool for administrative maintenance like this and there's often an existing script that does something similar to what you want.
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